Find last built commit

[zenogueira]

Hello,

Is there a way to know what the last built commit was on the current branch and pipeline?

We have many servers running builds from different branches at the same time on a few pipelines, and wanted to know at build start which was the last commit from that branch to be run on that pipeline.

Currently we git diff against the main development branch or HEAD, but this doesn’t give correct results, as branches drift apart, as well as we can push more than one commit at a time.

Is there a better solution already built-in?

Thank you

[lukasz-buildkite]

Hey @zenogueira

You can use our builds REST API for this.
It’d require an API Access Token with read_builds permission to be available via the environment variable $BUILDKITE_API_TOKEN.

A sample script that could be executed from the pipeline:

#!/usr/bin/env bash
set -euo pipefail

# Get last 2 successful builds from current branch
BUILDS=$(curl -sf -H "Authorization: Bearer ${BUILDKITE_API_TOKEN}" \
  "https://api.buildkite.com/v2/organizations/${BUILDKITE_ORGANIZATION_SLUG}/pipelines/${BUILDKITE_PIPELINE_SLUG}/builds?branch=${BUILDKITE_BRANCH}&state=passed&per_page=2")

CURRENT_BUILD_NUM="${BUILDKITE_BUILD_NUMBER}"
FIRST_BUILD_NUM=$(echo "$BUILDS" | jq -r '.[0].number')
FIRST_COMMIT=$(echo "$BUILDS" | jq -r '.[0].commit')
SECOND_COMMIT=$(echo "$BUILDS" | jq -r '.[1].commit // empty')

if [ "$CURRENT_BUILD_NUM" = "$FIRST_BUILD_NUM" ] && [ -n "$SECOND_COMMIT" ]; then
  LAST_COMMIT="$SECOND_COMMIT"
else
  LAST_COMMIT="$FIRST_COMMIT"
fi

echo "Current commit: ${BUILDKITE_COMMIT}"
echo "Last successful commit: ${LAST_COMMIT}"
echo "Commits since last build:"
git log --oneline "${LAST_COMMIT}".."${BUILDKITE_COMMIT}"

Depending on your usecase, GitHub - buildkite-plugins/annotate-git-diff-buildkite-plugin: A Buildkite plugin to show the diff of the current build compared to the previous one on a chosen branch. can be another option to consider.

[zenogueira]

That’s a good idea, I will take a look at it, and adapt it to our needs.

Thank you